Rushbrooke inequality

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In statistical mechanics, the Rushbrooke inequality relates the critical exponents of a magnetic system which exhibits a first-order phase transition in the thermodynamic limit for non-zero temperature T.

Since the Helmholtz free energy is extensive, the normalization to free energy per site is given as

$f = -kT \lim_{N \rightarrow \infty} \frac{1}{N}\log Z_N$

The magnetization M per site in the thermodynamic limit, depending on the external magnetic field H and temperature T is given by

$M(T,H) \equiv \lim_{N \rightarrow \infty} \frac{1}{N} \left( \sum_i \sigma_i \right) = - \left( \frac{\partial f}{\partial H} \right)_T$

where $σ i$ is the spin at the i-th site, and the magnetic susceptibility and specific heat at constant temperature and field are given by, respectively

$\chi_T(T,H) = \left( \frac{\partial M}{\partial H} \right)_T$

and

$c_H = -T \left( \frac{\partial^2 f}{\partial T^2} \right)_H.$

[edit] Definitions

The critical exponents $α,α',β,γ,γ'$ and $δ$ are defined in terms of the behaviour of the order parameters and response functions near the critical point as follows

$M(t,0) \simeq (-t)^{\beta}\mbox{ for }t \uparrow 0$

$M(0,H) \simeq |H|^{1/ \delta} \operatorname{sign}(H)\mbox{ for }H \rightarrow 0$

$\chi_T(t,0) \simeq \begin{cases} (t)^{-\gamma}, & \textrm{for} \ t \downarrow 0 \\ (-t)^{-\gamma'}, & \textrm{for} \ t \uparrow 0 \end{cases}$

$c_H(t,0) \simeq \begin{cases} (t)^{-\alpha} & \textrm{for} \ t \downarrow 0 \\ (-t)^{-\alpha'} & \textrm{for} \ t \uparrow 0 \end{cases}$

where

$t \equiv \frac{T-T_c}{T_c}$

measures the temperature relative to the critical point.

[edit] Derivation

For the magnetic analogue of the Maxwell relations for the response functions, the relation

$\chi_T (c_H -c_M) = T \left( \frac{\partial M}{\partial T} \right)_H^2$

follows, and with thermodynamic stability requiring that $c_h, c_M\mbox{ and }\chi_T \geq 0$ , one has

$c_H \geq \frac{T}{\chi_T} \left( \frac{\partial M}{\partial T} \right)_H^2$

which, under the conditions $H = 0, t < 0$ and the definition of the critical exponents gives

$(-t)^{-\alpha'} \geq \mathrm{constant}\cdot(-t)^{\gamma'}(-t)^{2(\beta-1)}$

which gives the Rushbrooke inequality

$\alpha' + 2\beta + \gamma' \geq 2.$

Remarkably, in experiment and in exactly solved models, the inequality actually holds as an inequality.

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Category: Statistical mechanics

Rushbrooke inequality

From Wikipedia, the free encyclopedia

[edit] Definitions

[edit] Derivation

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