Lewisville, Indiana

From Wikipedia, the free encyclopedia

Lewisville is a town in Henry County, Indiana, United States. The population was 395 at the 2000 census.

1 Geography
2 Demographics
3 External links
4 References

[edit] Geography

Lewisville is located at 39°48′26″N, 85°21′6″W (39.807221, -85.351549)^GR1, along the Flatrock River.^[1]

According to the United States Census Bureau, the town has a total area of 0.9 km² (0.3 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 395 people, 151 households, and 117 families residing in the town. The population density was 462.2/km² (1,206.4/mi²). There were 157 housing units at an average density of 183.7/km² (479.5/mi²). The racial makeup of the town was 99.24% White, and 0.76% from two or more races.

There were 151 households out of which 33.1% had children under the age of 18 living with them, 66.9% were married couples living together, 7.3% had a female householder with no husband present, and 21.9% were non-families. 19.2% of all households were made up of individuals and 11.9% had someone living alone who was 65 years of age or older. The average household size was 2.62 and the average family size was 2.97.

In the town the population was spread out with 23.8% under the age of 18, 10.4% from 18 to 24, 25.8% from 25 to 44, 21.5% from 45 to 64, and 18.5% who were 65 years of age or older. The median age was 39 years. For every 100 females there were 94.6 males. For every 100 females age 18 and over, there were 90.5 males.

The median income for a household in the town was $37,841, and the median income for a family was $43,750. Males had a median income of $34,750 versus $23,864 for females. The per capita income for the town was $15,476. About 4.5% of families and 8.3% of the population were below the poverty line, including 12.1% of those under age 18 and none of those age 65 or over.