Arley, Alabama

From Wikipedia, the free encyclopedia

Arley is a town in Winston County, Alabama, United States. At the 2000 census the population was 290. According to the 2005 U.S. Census estimates, the town had a population of 321. [1]

[edit] Geography

Arley is located at 34°4′53″N, 87°12′39″W (34.081499, -87.210768)^GR1.

According to the U.S. Census Bureau, the town has a total area of 7.3 km² (2.8 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 290 people, 123 households, and 89 families residing in the town. The population density was 40.0/km² (103.6/mi²). There were 139 housing units at an average density of 19.2/km² (49.7/mi²). The racial makeup of the town was 99.31% White, and 0.69% from two or more races. 1.38% of the population were Hispanic or Latino of any race.

There were 123 households out of which 22.0% had children under the age of 18 living with them, 60.2% were married couples living together, 9.8% had a female householder with no husband present, and 27.6% were non-families. 26.0% of all households were made up of individuals and 13.8% had someone living alone who was 65 years of age or older. The average household size was 2.36 and the average family size was 2.82.

In the town the population was spread out with 17.9% under the age of 18, 9.7% from 18 to 24, 26.6% from 25 to 44, 27.2% from 45 to 64, and 18.6% who were 65 years of age or older. The median age was 41 years. For every 100 females there were 100.0 males. For every 100 females age 18 and over, there were 91.9 males.

The median income for a household in the town was $26,500, and the median income for a family was $31,000. Males had a median income of $25,750 versus $16,667 for females. The per capita income for the town was $12,822. About 13.3% of families and 15.4% of the population were below the poverty line, including 25.0% of those under the age of eighteen and 22.6% of those sixty five or over.