United States presidential election, 2004, in Rhode Island
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Like all other New England states, Rhode Island was carried by Democratic candidate John F. Kerry, a United States senator from neighboring Massachusetts. Even though President George W. Bush fared better than in 2000, he was anyway overwhelmingly defeated in a traditional Democratic stronghold, winning only 38.67% of the vote to 59.42% for Kerry.
| Presidential Candidate | Running Mate | Party | Electoral Vote (EV) | Popular Vote (PV) | ||
|---|---|---|---|---|---|---|
| John Kerry of Massachusetts | John Edwards of North Carolina | Democrat | 4 | 259,760 | 59.42% | |
| George W. Bush of Texas | Richard Cheney of Wyoming | Republican | 0 | 169,046 | 38.67% | |
| Ralph Nader of Connecticut | Peter Camejo | Independent | 0 | 4,651 | 1.06% | |
| David Cobb of California | Patricia LaMarche of Maine | D.C. Statehood Green | 0 | 1,333 | 0.30% | |
| Others | - | - | 0 | 2,344 | 0.54% | |
| Other elections: 2000, 2004, 2008 | ||||||
Statewide winner in bold. See main article : U.S. presidential election, 2004.
[edit] Results by county
| County | John F. Kerry | George W. Bush | Others | |||
|---|---|---|---|---|---|---|
| Providence | 62.6% | 144,811 | 35.6% | 82,337 | 1.8% | 4,176 |
| Bristol | 58.4% | 14,448 | 39.8% | 9,855 | 1.7% | 429 |
| Newport | 56.9% | 22,992 | 41.1% | 16,622 | 2.0% | 812 |
| Washington | 55.4% | 34,679 | 42.4% | 26,533 | 2.3% | 1,422 |
| Kent | 54.9% | 42,830 | 43.2% | 33,699 | 1.9% | 1,489 |
