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贝尔数 - Wikipedia

贝尔数

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贝尔数以埃里克·坦普尔·貝尔(Eric Temple Bell)為名,是組合數學中的一組整數數列,開首是(OEIS的A000110數列):

B_0=1,\quad B_1=1,\quad B_2=2,\quad B_3=5,\quad B_4=15,\quad B_5=52,\quad B_6=203,\quad\dots

Bn基數n的集合的劃分方法的數目。集合S的一個劃分是定義為S的兩兩不相交的非空子集的族,它們的並是S。例如B3 = 5因為3個元素的集合{abc}有5種不同的劃分方法:

{{a}, {b}, {c}}
{{a}, {b, c}}
{{b}, {a, c}}
{{c}, {a, b}}
{{a, b, c}}

B0是1因為空集正好有1種劃分方法。空集的每個成員都是非空集合(這是空虛的真),而它們的並是空集本身。所以空集是它的唯一劃分。

貝爾數適合遞推公式:

B_{n+1}=\sum_{k=0}^{n}{{n \choose k}B_k}.

它們也適合「Dobinski公式」:

B_n=\frac{1}{e}\sum_{k=0}^\infty \frac{k^n}{k!}=期望值為1的泊松分數的n次矩。

它們也適合「Touchard同餘」:若p是任意質數,那麼

B_{p+n}\equiv B_n+B_{n+1}\ (\operatorname{mod}\ p).

每個貝爾數都是"第二類Stirling數"的和

B_n=\sum_{k=1}^n S(n,k).

Stirling數S(n, k)是把基數為n的集劃分為正好k個非空集的方法的數目。

把任一概率分佈n以首n個累積量表示的多項式,其係數和正是第n個貝爾數。這種數劃分的方法不像用Stirling數那個方法粗糙。

貝爾數的指數母函數是

\sum_{n=0}^\infty \frac{B_n}{n!} x^n = e^{e^x-1}.

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