Zerbolò
From Wikipedia, the free encyclopedia
| Zerbolò | |
|---|---|
| Country |  Italy |
| Region | Lombardy |
| Province | Province of Pavia (PV) |
| Mayor | |
| Elevation | m |
| Area | 37.8 km² |
| Population | |
| - Total (as of Dec. 2004) | 1,277 |
| - Density | 34/km² |
| Time zone | CET, UTC+1 |
| Coordinates | |
| Gentilic | |
| Dialing code | 0382 |
| Postal code | 27020 |
  Location of Zerbolò in Italy |
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Zerbolò is a comune (municipality) in the Province of Pavia in the Italian region Lombardy, located about 30 km southwest of Milan and about 11 km west of Pavia. As of 31 December 2004, it had a population of 1,277 and an area of 37.8 km2.[1]
Zerbolò borders the following municipalities: Bereguardo, Borgo San Siro, Carbonara al Ticino, Garlasco, Gropello Cairoli, Torre d'Isola, Villanova d'Ardenghi.
[edit] Demographic evolution
[edit] References
Lombardy · Communes of the province of Pavia
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