Dennehotso, Arizona

From Wikipedia, the free encyclopedia

Dennehotso (Navajo: Deinihootso) is a census-designated place (CDP) in Apache County, Arizona, United States. At the 2000 census the population was 734.

1 Geography
2 Demographics
3 Education
4 External links

[edit] Geography

Dennehotso is located at 36°50′14″N, 109°51′39″W (36.837286, -109.860884)^GR1.

According to the United States Census Bureau, the CDP has a total area of 25.7 km² (9.9 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 734 people, 168 households, and 141 families residing in the CDP. The population density was 28.5/km² (73.8/mi²). There were 233 housing units at an average density of 9.1/km² (23.4/mi²). The racial makeup of the CDP was 98.64% Native American, 0.82% White, and 0.54% from two or more races. 0.27% of the population were Hispanic or Latino of any race.

There were 168 households out of which 56.5% had children under the age of 18 living with them, 55.4% were married couples living together, 24.4% had a female householder with no husband present, and 15.5% were non-families. 14.9% of all households were made up of individuals and 5.4% had someone living alone who was 65 years of age or older. The average household size was 4.37 and the average family size was 4.92.

In the CDP the population was spread out with 44.6% under the age of 18, 9.4% from 18 to 24, 24.5% from 25 to 44, 15.4% from 45 to 64, and 6.1% who were 65 years of age or older. The median age was 21 years. For every 100 females there were 100.5 males. For every 100 females age 18 and over, there were 106.6 males.

The median income for a household in the CDP was $19,844, and the median income for a family was $21,944. Males had a median income of $27,143 versus $16,250 for females. The per capita income for the CDP was $5,445. About 37.0% of families and 40.6% of the population were below the poverty line, including 47.9% of those under age 18 and 28.9% of those age 65 or over.